[Mono-list] RE: Support for .NET/COM interoperability
Robik, Scott
scott.robik@csfb.com
Mon, 3 Jan 2005 16:54:58 -0000
Erik,
If I understand your response correctly, in order to access COM calculators =
that I currently have, I would also need to be running the COM runtime on the=
=
UNIX host. If this is true then it sound like my only option would be to port=
=
the calculators to UNIX. I was looking to use MONO as a cross platform bridge=
=
to allow me to get to these COM servers without having to port them to UNIX. =
Are there any vendors providing COM on UNIX that your aware of=3F
Regards,
Scott L. Robik
-----Original Message-----
=46rom: Erik Dasque [mailto:edasque@ximian.com]
Sent: Monday, January 03, 2005 11:41 AM
To: Robik, Scott
Subject: Re: Support for .NET/COM interoperability
No we do not. There is no reliable COM implementation on UNIX to =20
interface with.
Erik
On Dec 13, 2004, at 2:53 PM, Robik, Scott wrote:
> To whom it may concern,
> =A0
> I'm mostly interested in building large scale server side numerical =20
> applications. We have a very extensive set of calculators for valuing =20
> financial securities and computing various risk scenarios that are all =20
> written using COM. I'm very interested in using these on LINUX. Does =20
> Mono support the System.Runtime.InteropServices=A0namespace=3F
>
> =A0
>
> Scott L. Robik
>
> Securities IT
>
>
> Credit Suisse First Boston
> One Madison Avenue
> New York, NY. 10010
>
> ( (212) 538-0165
>
> * Scott.Robik@csfb.com
>
> <image.tiff>=A0
>
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This message is for the sole use of the intended recipient. If you received =
this message in error please delete it and notify us. If this message was =
misdirected, CSFB does not waive any confidentiality or privilege. CSFB =
retains and monitors electronic communications sent through its network. =
Instructions transmitted over this system are not binding on CSFB until they =
are confirmed by us. Message transmission is not guaranteed to be secure.
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
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