[Mono-list] XML reading problem

[Daniel Lo Nigro]

This sounds like a job for the XML serializer (eg.
http://geekswithblogs.net/TimH/archive/2006/02/09/68857.aspx). You should
be able to use an XML deserializer (either the standard .NET one or a
custom one) to parse your XML into objects. Mapping XML to objects is
pretty common and a XML deserializer should be able to do most of the work
for you. :)

Otherwise, I'd suggest using LINQ to XML instead. Use XElement.Load to load
the XML file, file.Descendants("GirlRecord") to get the records and
record.Element("FirstName") to get the value.


On Thu, Mar 14, 2013 at 2:58 AM, Paul Johnson
<paul at all-the-johnsons.co.uk>wrote:

> Hi,
>
> Got a small XML issue I could do with some help on.
>
> I have an XML file that looks like this
>
> <GirlRecord>
> <FirstName>Girly</FirstName>
> <LastName>Girl</LastName>
> ...
> </GirlRecord>
>
> The GirlRecord can contain upto 50 different fields - it doesn't have to
> contain all of them (so a record with 26 fields is fine).
>
> I have a containing class which looks like this
>
> public class GirlRecords
> {
>    public GirlRecords(){}
>
>    public string FirstName
>    {get;set;}
>    public string LastName
>    {get;set;}
>
>    // and so on
> }
>
> To load the XML file back in, my code looks like this
>
> private List<GirlRecords> ReadInGirlRecords()
>         {
>             List<GirlRecords> toReturn = new List<GirlRecords>();
>             GirlRecords aff = null;
>             int m = 0;
>             string localPath = Path.Combine(path, "GirlRecords.xml");
>             if (!File.Exists(localPath))
>                 return toReturn;
>             using (XmlReader reader = XmlReader.Create(localPath))
>             {
>                 aff = new GirlRecords();
>                 while (reader.Read())
>                 {
>                     if (reader.IsStartElement())
>                     {
>                         switch (reader.Name)
>                         {
>                             case "FirstName":
>                                 reader.Read();
>                                 aff.FirstName = reader.Value;
>                                 break;
>                             case "LastName":
>                                 reader.Read();
>                                 aff.LastName = reader.Value;
>                                 break;
>
> The problem is that to add to the List, I need to find the terminating
> </GirlRecord> and act on that.
>
> Question is, how do I do that? Should I use XmlReadInner or ReadOuter or
> is there a better way?
>
> Paul
>
> --
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> hugely, mindbogglingly big it is. I mean, you may think it's a long way
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>
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