[Mono-bugs] [Bug 495562] Calling Show() on a maximized form changes Window state to Normal .NET difference

bugzilla_noreply at novell.com bugzilla_noreply at novell.com
Mon Apr 27 00:59:06 EDT 2009


User calberto.cortez at gmail.com added comment

Carlos Alberto Cortez <calberto.cortez at gmail.com> changed:

           What    |Removed                     |Added
                 CC|                            |calberto.cortez at gmail.com

--- Comment #2 from Carlos Alberto Cortez <calberto.cortez at gmail.com>  2009-04-26 22:59:04 MDT ---
Actually this is a known issue related to our implementation being
asynchronous, which shows for Show (). Basically calling Form.Show () will not
execute all the routines commonly executed in a form being shown, since it gets

This doesn't happend with a) Forms calling ShowDialog (), which means the forms
stay *in* the screen, b) Forms passed to Application.Run, also remaining in the
screen, and c) Forms calling Show () when there's already another Form running
- which forces the form to stay alive.

To test that, I tested it with the attached sample:

using System;
using System.Windows.Forms;

namespace ConsoleApplicationRegTest
    class Program
        static void Main(string[] args)
            Form f = new Form ();

            Button b = new Button ();
            b.Click += delegate 
                Form f2 = new Form ();
                f2.WindowState = FormWindowState.Maximized;
                f2.Show ();
            b.Dock = DockStyle.Fill;
            b.Text = "show win";
            b.Parent = f;

            Application.Run (f);

Basically, after running a first Form with Application.Run, we show a second
form after pressing a button - as you can see, this second form is actually
maximized, since *all* the routines are executed for it (inclusing telling the
window manager we want it to be maximized).

As I said, it's a known issue, and it's unlikely to affect real world apps,
since basically nobody uses Form.Show without other forms already running/using
ShowDialog ()/Application.Run

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