[Mono-bugs] [Bug 79441][Nor] Changed - String.IsInterned doesn't work as expected
bugzilla-daemon at bugzilla.ximian.com
bugzilla-daemon at bugzilla.ximian.com
Tue Sep 19 08:34:13 EDT 2006
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Changed by kornelpal at gmail.com.
http://bugzilla.ximian.com/show_bug.cgi?id=79441
--- shadow/79441 2006-09-19 08:25:23.000000000 -0400
+++ shadow/79441.tmp.5187 2006-09-19 08:34:13.000000000 -0400
@@ -1,13 +1,13 @@
Bug#: 79441
Product: Mono: Runtime
Version: 1.1
OS: GNU/Linux [Other]
OS Details:
-Status: NEW
-Resolution:
+Status: RESOLVED
+Resolution: NOTABUG
Severity: Unknown
Priority: Normal
Component: misc
AssignedTo: mono-bugs at ximian.com
ReportedBy: pawel.sakowski at mindbreeze.com
QAContact: mono-bugs at ximian.com
@@ -50,6 +50,46 @@
Additional Information:
mono 1.1.13.6
------- Additional Comments From robertj at gmx.net 2006-09-19 08:25 -------
That's a documentation bug.
+
+------- Additional Comments From kornelpal at gmail.com 2006-09-19 08:34 -------
+The property behaves as expected because it informs you that the
+string is not interned.
+
+Only string literals are interned by default.
+
+Note that MS.NET prints False as well.
+
+If you need a True, use this:
+using System;
+using System.Text;
+
+public class StringExample {
+ public static void Main() {
+
+ String s1 = String.Intern(new StringBuilder().Append
+("My").Append("Test").ToString());
+
+ Console.WriteLine(String.IsInterned(s1) != null);
+ }
+}
+
+Or this:
+using System;
+using System.Text;
+
+public class StringExample {
+ public static void Main() {
+
+ String s1 = new StringBuilder().Append("My").Append
+("Test").ToString();
+ String s2 = "MyTest";
+
+ Console.WriteLine(String.IsInterned(s1) != null);
+ // This is not required I only added to ensure that s2
+ // won't be optimized out.
+ GC.KeepAlive(s2);
+ }
+}
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