[Mono-bugs] [Bug 58256][Nor] Changed - [PATCH] Replace Doesn't Replace ' Correctly

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Changed by kjambunathan@novell.com.

http://bugzilla.ximian.com/show_bug.cgi?id=58256

--- shadow/58256	2004-05-14 00:59:44.000000000 -0400
+++ shadow/58256.tmp.1677	2004-05-14 02:02:11.000000000 -0400
@@ -102,6 +102,22 @@
 Patch for Original Bug 58256
 
 
 ------- Additional Comments From kjambunathan@novell.com  2004-05-13 10:32 -------
 Parse Escape is not handling the following Escape Sequences \b and
 \*(say ). I am an attaching a patch for the same as well.
+
+------- Additional Comments From kjambunathan@novell.com  2004-05-14 02:02 -------
+According to the MS documentation:
+
+"In a regular expression, \b denotes a word boundary (between \w and
+\W characters) except within a [] character class, where \b refers to
+the backspace character. In a replacement pattern, \b always denotes a
+backspace."
+
+Initially, I suspected that a trivial modification to ParseEscape()
+will suffice. Later I realised that \b is handled differently based
+upon the context. I need to investigate whether the obvious
+modiifcation to ParseEscape() will create unwanted side-effects wrt to
+parsing of \b in other contexts.
+
+